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x→ |
1 | 2 |

y↓ |
||

1 | 0.4 | 0.2 |

2 | 0.1 | 0.3 |

Then E(x|y = 1) is:

This question was previously asked in

SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )

- 2 / 3
- 5 / 3
- 2
- 4 / 3

Option 4 : 4 / 3

Free

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306304

10 Questions
10 Marks
7 Mins

**Formula**

E(x/y = 1) = ∑x_{j} P(x = xy/y = 1

**Calculation**

According to the formula

⇒ 1 × (0.4/0.3)

⇒ 4/3

**∴ The E(x|y = 1) is: 4/3**

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